Search a number
-
+
413300211103 = 13193211780697
BaseRepresentation
bin1100000001110101001…
…11001011110110011111
31110111210121021002200001
412000322213023312133
523232414323223403
6513511213515131
741600651554453
oct6007247136637
91414717232601
10413300211103
1114a3092158aa
12681254a2aa7
132cc87c82c40
141600a758663
15ab3e39bc1d
hex603a9cbd9f

413300211103 has 16 divisors (see below), whose sum is σ = 449519662816. Its totient is φ = 377731952640.

The previous prime is 413300211067. The next prime is 413300211109. The reversal of 413300211103 is 301112003314.

It is a cyclic number.

It is not a de Polignac number, because 413300211103 - 29 = 413300210591 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (413300211109) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 139051 + ... + 919747.

It is an arithmetic number, because the mean of its divisors is an integer number (28094978926).

Almost surely, 2413300211103 is an apocalyptic number.

413300211103 is a deficient number, since it is larger than the sum of its proper divisors (36219451713).

413300211103 is a wasteful number, since it uses less digits than its factorization.

413300211103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 781114.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 413300211103 its reverse (301112003314), we get a palindrome (714412214417).

It can be divided in two parts, 413300 and 211103, that added together give a triangular number (624403 = T1117).

The spelling of 413300211103 in words is "four hundred thirteen billion, three hundred million, two hundred eleven thousand, one hundred three".

Divisors: 1 13 193 211 2509 2743 40723 529399 780697 10149061 150674521 164727067 1958768773 2141451871 31792323931 413300211103