Base | Representation |
---|---|
bin | 111100001001001011001… |
… | …100110111100100110010 |
3 | 112122010001021200011121222 |
4 | 330021023030313210302 |
5 | 1020203411133001224 |
6 | 12442403330345042 |
7 | 604413044040002 |
oct | 74111314674462 |
9 | 15563037604558 |
10 | 4133020203314 |
11 | 13538931801a2 |
12 | 56901012b182 |
13 | 23c985609602 |
14 | 104079990002 |
15 | 72799053b5e |
hex | 3c24b337932 |
4133020203314 has 4 divisors (see below), whose sum is σ = 6199530304974. Its totient is φ = 2066510101656.
The previous prime is 4133020203311. The next prime is 4133020203329.
4133020203314 is nontrivially palindromic in base 10.
4133020203314 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 4081543400089 + 51476803225 = 2020283^2 + 226885^2 .
It is not an unprimeable number, because it can be changed into a prime (4133020203311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1033255050827 + ... + 1033255050830.
Almost surely, 24133020203314 is an apocalyptic number.
4133020203314 is a deficient number, since it is larger than the sum of its proper divisors (2066510101660).
4133020203314 is a wasteful number, since it uses less digits than its factorization.
4133020203314 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2066510101659.
The product of its (nonzero) digits is 5184, while the sum is 26.
It can be divided in two parts, 4133020 and 203314, that added together give a palindrome (4336334).
The spelling of 4133020203314 in words is "four trillion, one hundred thirty-three billion, twenty million, two hundred three thousand, three hundred fourteen".
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