Base | Representation |
---|---|
bin | 10010110010111001001101… |
… | …10010011001001110011111 |
3 | 12102100012211212222210122211 |
4 | 21121130212302121032133 |
5 | 20404132113441043033 |
6 | 223523131015421251 |
7 | 11464034465124163 |
oct | 1131344662311637 |
9 | 172305755883584 |
10 | 41331121034143 |
11 | 12195480361896 |
12 | 47762b8984827 |
13 | 1a0a67b0909b5 |
14 | a2c618d24ca3 |
15 | 4ba1b5da92cd |
hex | 259726c9939f |
41331121034143 has 4 divisors (see below), whose sum is σ = 41332422054960. Its totient is φ = 41329820013328.
The previous prime is 41331121034131. The next prime is 41331121034173. The reversal of 41331121034143 is 34143012113314.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-41331121034143 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (41331121034113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 650462755 + ... + 650526292.
It is an arithmetic number, because the mean of its divisors is an integer number (10333105513740).
Almost surely, 241331121034143 is an apocalyptic number.
41331121034143 is a deficient number, since it is larger than the sum of its proper divisors (1301020817).
41331121034143 is a wasteful number, since it uses less digits than its factorization.
41331121034143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1301020816.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 41331121034143 its reverse (34143012113314), we get a palindrome (75474133147457).
The spelling of 41331121034143 in words is "forty-one trillion, three hundred thirty-one billion, one hundred twenty-one million, thirty-four thousand, one hundred forty-three".
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