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41331134113 = 231797005831
BaseRepresentation
bin100110011111100001…
…110000111010100001
310221200102211011012221
4212133201300322201
51134121232242423
630553125351041
72662136562163
oct463741607241
9127612734187
1041331134113
111658a390885
128015868481
133b88a9b799
1420012b4933
15111d7c6e5d
hex99f870ea1

41331134113 has 4 divisors (see below), whose sum is σ = 43128139968. Its totient is φ = 39534128260.

The previous prime is 41331134101. The next prime is 41331134147. The reversal of 41331134113 is 31143113314.

41331134113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 41331134113 - 221 = 41329036961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (41331134813) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 898502893 + ... + 898502938.

It is an arithmetic number, because the mean of its divisors is an integer number (10782034992).

Almost surely, 241331134113 is an apocalyptic number.

It is an amenable number.

41331134113 is a deficient number, since it is larger than the sum of its proper divisors (1797005855).

41331134113 is a wasteful number, since it uses less digits than its factorization.

41331134113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1797005854.

The product of its digits is 1296, while the sum is 25.

Adding to 41331134113 its reverse (31143113314), we get a palindrome (72474247427).

The spelling of 41331134113 in words is "forty-one billion, three hundred thirty-one million, one hundred thirty-four thousand, one hundred thirteen".

Divisors: 1 23 1797005831 41331134113