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4140120012320 = 2551917936720731
BaseRepresentation
bin111100001111110010011…
…000011111011000100000
3112122210101002012211122002
4330033302120133120200
51020312431210343240
612445540032103132
7605054014314425
oct74176230373040
915583332184562
104140120012320
1113568a68a5846
1256a471994aa8
132405474ba126
1410455088bd4c
1572a624d5d15
hex3c3f261f620

4140120012320 has 192 divisors, whose sum is σ = 10382054860800. Its totient is φ = 1555796782080.

The previous prime is 4140120012311. The next prime is 4140120012349. The reversal of 4140120012320 is 232100210414.

4140120012320 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 4140120012292 and 4140120012301.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 199696355 + ... + 199717085.

It is an arithmetic number, because the mean of its divisors is an integer number (54073202400).

Almost surely, 24140120012320 is an apocalyptic number.

4140120012320 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 4140120012320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (5191027430400).

4140120012320 is an abundant number, since it is smaller than the sum of its proper divisors (6241934848480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

4140120012320 is a wasteful number, since it uses less digits than its factorization.

4140120012320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21311 (or 21303 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 4140120012320 its reverse (232100210414), we get a palindrome (4372220222734).

The spelling of 4140120012320 in words is "four trillion, one hundred forty billion, one hundred twenty million, twelve thousand, three hundred twenty".