Base | Representation |
---|---|
bin | 10010110101001110001111… |
… | …10100000010111110100011 |
3 | 12102121212100222202112020221 |
4 | 21122213013310002332203 |
5 | 20411434444243313103 |
6 | 224024002244343511 |
7 | 11502566312162431 |
oct | 1132470764027643 |
9 | 172555328675227 |
10 | 41411132010403 |
11 | 122163a9485561 |
12 | 47899083a4b97 |
13 | 1a1508c56982c |
14 | a32449319d51 |
15 | 4bc2ea2e51bd |
hex | 25a9c7d02fa3 |
41411132010403 has 8 divisors (see below), whose sum is σ = 41580693472608. Its totient is φ = 41241635887104.
The previous prime is 41411132010397. The next prime is 41411132010461. The reversal of 41411132010403 is 30401023111414.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 41411132010403 - 25 = 41411132010371 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (41411132010463) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15064351 + ... + 17599912.
It is an arithmetic number, because the mean of its divisors is an integer number (5197586684076).
Almost surely, 241411132010403 is an apocalyptic number.
41411132010403 is a deficient number, since it is larger than the sum of its proper divisors (169561462205).
41411132010403 is a wasteful number, since it uses less digits than its factorization.
41411132010403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32669453.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 41411132010403 its reverse (30401023111414), we get a palindrome (71812155121817).
It can be divided in two parts, 4141113 and 2010403, that added together give a palindrome (6151516).
The spelling of 41411132010403 in words is "forty-one trillion, four hundred eleven billion, one hundred thirty-two million, ten thousand, four hundred three".
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