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414152133001 = 1379930013199
BaseRepresentation
bin1100000011011010110…
…01000000100110001001
31110120222222022012210221
412001231121000212021
523241140421224001
6514131525310041
741631035021665
oct6015531004611
91416888265727
10414152133001
1114a70609a392
1268322865321
1330092614c39
141608b95b8a5
15ab8e07d1a1
hex606d640989

414152133001 has 4 divisors (see below), whose sum is σ = 414182160000. Its totient is φ = 414122106004.

The previous prime is 414152132981. The next prime is 414152133011. The reversal of 414152133001 is 100331251414.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 414152133001 - 237 = 276713179529 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (414152133011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14992801 + ... + 15020398.

It is an arithmetic number, because the mean of its divisors is an integer number (103545540000).

Almost surely, 2414152133001 is an apocalyptic number.

It is an amenable number.

414152133001 is a deficient number, since it is larger than the sum of its proper divisors (30026999).

414152133001 is a wasteful number, since it uses less digits than its factorization.

414152133001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30026998.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 414152133001 its reverse (100331251414), we get a palindrome (514483384415).

The spelling of 414152133001 in words is "four hundred fourteen billion, one hundred fifty-two million, one hundred thirty-three thousand, one".

Divisors: 1 13799 30013199 414152133001