Base | Representation |
---|---|
bin | 111100010010110000000… |
… | …111000101100100111101 |
3 | 112200002120220210112011001 |
4 | 330102300013011210331 |
5 | 1020340441044334323 |
6 | 12451223541130301 |
7 | 605225625304324 |
oct | 74226007054475 |
9 | 15602526715131 |
10 | 4143303121213 |
11 | 135818a661653 |
12 | 56abbb9b9991 |
13 | 240933ac3609 |
14 | 10477351b0bb |
15 | 72b9bb993ad |
hex | 3c4b01c593d |
4143303121213 has 4 divisors (see below), whose sum is σ = 4361371706560. Its totient is φ = 3925234535868.
The previous prime is 4143303121201. The next prime is 4143303121247. The reversal of 4143303121213 is 3121213033414.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4143303121213 - 29 = 4143303120701 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4143303121253) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 109034292645 + ... + 109034292682.
It is an arithmetic number, because the mean of its divisors is an integer number (1090342926640).
Almost surely, 24143303121213 is an apocalyptic number.
It is an amenable number.
4143303121213 is a deficient number, since it is larger than the sum of its proper divisors (218068585347).
4143303121213 is a wasteful number, since it uses less digits than its factorization.
4143303121213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 218068585346.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 4143303121213 its reverse (3121213033414), we get a palindrome (7264516154627).
The spelling of 4143303121213 in words is "four trillion, one hundred forty-three billion, three hundred three million, one hundred twenty-one thousand, two hundred thirteen".
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