4144012133 has 4 divisors (see below), whose sum is σ = 4144750080. Its totient is φ = 4143274188.

The previous prime is 4144012129. The next prime is 4144012183. The reversal of 4144012133 is 3312104414.

4144012133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4144012133 - 2² = 4144012129 is a prime.

It is a super-4 number, since 4×4144012133⁴ (a number of 40 digits) contains 4444 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4144012099 and 4144012108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4144012183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 360485 + ... + 371802.

It is an arithmetic number, because the mean of its divisors is an integer number (1036187520).

Almost surely, 2^4144012133 is an apocalyptic number.

It is an amenable number.

4144012133 is a deficient number, since it is larger than the sum of its proper divisors (737947).

4144012133 is an equidigital number, since it uses as much as digits as its factorization.

4144012133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 737946.

The product of its (nonzero) digits is 1152, while the sum is 23.

The square root of 4144012133 is about 64374.0019961475. The cubic root of 4144012133 is about 1606.2273112452.

Adding to 4144012133 its reverse (3312104414), we get a palindrome (7456116547).

The spelling of 4144012133 in words is "four billion, one hundred forty-four million, twelve thousand, one hundred thirty-three".