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4144334021411 = 7377175617783
BaseRepresentation
bin111100010011101101100…
…011101010001100100011
3112200012020202121200100212
4330103231203222030203
51020400044002141121
612451514125004335
7605263313643263
oct74235543521443
915605222550325
104144334021411
111358669570191
1256b2490b36ab
13240a6955c42c
141048303cd7a3
1572c0c43125b
hex3c4ed8ea323

4144334021411 has 4 divisors (see below), whose sum is σ = 4144340376912. Its totient is φ = 4144327665912.

The previous prime is 4144334021381. The next prime is 4144334021419. The reversal of 4144334021411 is 1141204334414.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4144334021411 - 238 = 3869456114467 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4144334021419) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2071175 + ... + 3546608.

It is an arithmetic number, because the mean of its divisors is an integer number (1036085094228).

Almost surely, 24144334021411 is an apocalyptic number.

4144334021411 is a deficient number, since it is larger than the sum of its proper divisors (6355501).

4144334021411 is an equidigital number, since it uses as much as digits as its factorization.

4144334021411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6355500.

The product of its (nonzero) digits is 18432, while the sum is 32.

Adding to 4144334021411 its reverse (1141204334414), we get a palindrome (5285538355825).

The spelling of 4144334021411 in words is "four trillion, one hundred forty-four billion, three hundred thirty-four million, twenty-one thousand, four hundred eleven".

Divisors: 1 737717 5617783 4144334021411