Base | Representation |
---|---|
bin | 111100011100001010101… |
… | …001100100000111000001 |
3 | 112201001200102111222011010 |
4 | 330130022221210013001 |
5 | 1021022141440340301 |
6 | 12500015014311133 |
7 | 606034264601151 |
oct | 74341251440701 |
9 | 15631612458133 |
10 | 4153412043201 |
11 | 13614a7901333 |
12 | 570b613584a9 |
13 | 241885229565 |
14 | 105051d14761 |
15 | 7308e3c05d6 |
hex | 3c70aa641c1 |
4153412043201 has 16 divisors (see below), whose sum is σ = 5673669115968. Its totient is φ = 2701065216000.
The previous prime is 4153412043197. The next prime is 4153412043223. The reversal of 4153412043201 is 1023402143514.
It is not a de Polignac number, because 4153412043201 - 22 = 4153412043197 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (4153412043241) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1150975 + ... + 3103476.
It is an arithmetic number, because the mean of its divisors is an integer number (354604319748).
Almost surely, 24153412043201 is an apocalyptic number.
4153412043201 is a gapful number since it is divisible by the number (41) formed by its first and last digit.
It is an amenable number.
4153412043201 is a deficient number, since it is larger than the sum of its proper divisors (1520257072767).
4153412043201 is a wasteful number, since it uses less digits than its factorization.
4153412043201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4262432.
The product of its (nonzero) digits is 11520, while the sum is 30.
Adding to 4153412043201 its reverse (1023402143514), we get a palindrome (5176814186715).
It can be divided in two parts, 415341 and 2043201, that added together give a palindrome (2458542).
The spelling of 4153412043201 in words is "four trillion, one hundred fifty-three billion, four hundred twelve million, forty-three thousand, two hundred one".
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