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42014110011 = 314004703337
BaseRepresentation
bin100111001000001111…
…000111000100111011
311000110000221221000120
4213020033013010323
51142021103010021
631145004104323
73015102020436
oct471017070473
9130400857016
1042014110011
11168aa962775
1281865350a3
133c6742a133
142067c9a81d
15115d7352c6
hex9c83c713b

42014110011 has 4 divisors (see below), whose sum is σ = 56018813352. Its totient is φ = 28009406672.

The previous prime is 42014110009. The next prime is 42014110013. The reversal of 42014110011 is 11001141024.

42014110011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (42014110009) and next prime (42014110013).

It is a cyclic number.

It is not a de Polignac number, because 42014110011 - 21 = 42014110009 is a prime.

It is not an unprimeable number, because it can be changed into a prime (42014110013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7002351666 + ... + 7002351671.

It is an arithmetic number, because the mean of its divisors is an integer number (14004703338).

Almost surely, 242014110011 is an apocalyptic number.

42014110011 is a deficient number, since it is larger than the sum of its proper divisors (14004703341).

42014110011 is a wasteful number, since it uses less digits than its factorization.

42014110011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14004703340.

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 42014110011 its reverse (11001141024), we get a palindrome (53015251035).

The spelling of 42014110011 in words is "forty-two billion, fourteen million, one hundred ten thousand, eleven".

Divisors: 1 3 14004703337 42014110011