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42104134113 = 314034711371
BaseRepresentation
bin100111001101100110…
…100001100111100001
311000200022100121212120
4213031212201213201
51142212124242423
631201541414453
73020244143406
oct471546414741
9130608317776
1042104134113
1116946760158
1281b070a429
133c7cc8a032
142075c122ad
1511665b8ee3
hex9cd9a19e1

42104134113 has 4 divisors (see below), whose sum is σ = 56138845488. Its totient is φ = 28069422740.

The previous prime is 42104134067. The next prime is 42104134123. The reversal of 42104134113 is 31143140124.

42104134113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 42104134113 - 221 = 42102036961 is a prime.

It is not an unprimeable number, because it can be changed into a prime (42104134123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7017355683 + ... + 7017355688.

It is an arithmetic number, because the mean of its divisors is an integer number (14034711372).

Almost surely, 242104134113 is an apocalyptic number.

It is an amenable number.

42104134113 is a deficient number, since it is larger than the sum of its proper divisors (14034711375).

42104134113 is a wasteful number, since it uses less digits than its factorization.

42104134113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14034711374.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 42104134113 its reverse (31143140124), we get a palindrome (73247274237).

The spelling of 42104134113 in words is "forty-two billion, one hundred four million, one hundred thirty-four thousand, one hundred thirteen".

Divisors: 1 3 14034711371 42104134113