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42131400433 = 157523513103
BaseRepresentation
bin100111001111001110…
…100010011011110001
311000202012122220020021
4213033032202123301
51142241114303213
631204354043441
73021024665143
oct471716423361
9130665586207
1042131400433
1116960093801
1281b9879581
133c85815955
1420796acc93
151168ba2d8d
hex9cf3a26f1

42131400433 has 8 divisors (see below), whose sum is σ = 42480906368. Its totient is φ = 41782922064.

The previous prime is 42131400403. The next prime is 42131400439. The reversal of 42131400433 is 33400413124.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 42131400433 - 25 = 42131400401 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 42131400398 and 42131400407.

It is not an unprimeable number, because it can be changed into a prime (42131400439) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 174441 + ... + 338662.

It is an arithmetic number, because the mean of its divisors is an integer number (5310113296).

Almost surely, 242131400433 is an apocalyptic number.

It is an amenable number.

42131400433 is a deficient number, since it is larger than the sum of its proper divisors (349505935).

42131400433 is a wasteful number, since it uses less digits than its factorization.

42131400433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 513783.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 42131400433 its reverse (33400413124), we get a palindrome (75531813557).

The spelling of 42131400433 in words is "forty-two billion, one hundred thirty-one million, four hundred thousand, four hundred thirty-three".

Divisors: 1 157 523 82111 513103 80557171 268352869 42131400433