Base | Representation |
---|---|
bin | 111101010011110110111… |
… | …100011111001001011001 |
3 | 112220210000220210210102221 |
4 | 331103312330133021121 |
5 | 1023012124004021213 |
6 | 12543304501424041 |
7 | 613252203422230 |
oct | 75236674371131 |
9 | 15823026723387 |
10 | 4213211001433 |
11 | 13848a3854775 |
12 | 58066ba0b021 |
13 | 2473c5126205 |
14 | 107cc5bd3b17 |
15 | 748de16038d |
hex | 3d4f6f1f259 |
4213211001433 has 16 divisors (see below), whose sum is σ = 4819424400000. Its totient is φ = 3608079743232.
The previous prime is 4213211001431. The next prime is 4213211001457. The reversal of 4213211001433 is 3341001123124.
It is a cyclic number.
It is not a de Polignac number, because 4213211001433 - 21 = 4213211001431 is a prime.
It is a super-2 number, since 2×42132110014332 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4213211001398 and 4213211001407.
It is not an unprimeable number, because it can be changed into a prime (4213211001431) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 114629943 + ... + 114666691.
It is an arithmetic number, because the mean of its divisors is an integer number (301214025000).
Almost surely, 24213211001433 is an apocalyptic number.
It is an amenable number.
4213211001433 is a deficient number, since it is larger than the sum of its proper divisors (606213398567).
4213211001433 is a wasteful number, since it uses less digits than its factorization.
4213211001433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51024.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 4213211001433 its reverse (3341001123124), we get a palindrome (7554212124557).
The spelling of 4213211001433 in words is "four trillion, two hundred thirteen billion, two hundred eleven million, one thousand, four hundred thirty-three".
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