Base | Representation |
---|---|
bin | 1100010000110010111… |
… | …01101010111000000011 |
3 | 1111021112111021000121121 |
4 | 12020121131222320003 |
5 | 23400343001100303 |
6 | 521320321533111 |
7 | 42304022636041 |
oct | 6103135527003 |
9 | 1437474230547 |
10 | 421334003203 |
11 | 152761073803 |
12 | 697a7aa4197 |
13 | 309684c8089 |
14 | 1656d6db391 |
15 | ae5e81e9bd |
hex | 621976ae03 |
421334003203 has 4 divisors (see below), whose sum is σ = 422247960288. Its totient is φ = 420420046120.
The previous prime is 421334003179. The next prime is 421334003249. The reversal of 421334003203 is 302300433124.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 421334003203 - 25 = 421334003171 is a prime.
It is a super-2 number, since 2×4213340032032 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (421334003303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 456977851 + ... + 456978772.
It is an arithmetic number, because the mean of its divisors is an integer number (105561990072).
Almost surely, 2421334003203 is an apocalyptic number.
421334003203 is a deficient number, since it is larger than the sum of its proper divisors (913957085).
421334003203 is an equidigital number, since it uses as much as digits as its factorization.
421334003203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 913957084.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 421334003203 its reverse (302300433124), we get a palindrome (723634436327).
The spelling of 421334003203 in words is "four hundred twenty-one billion, three hundred thirty-four million, three thousand, two hundred three".
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