Base | Representation |
---|---|
bin | 1100010010101010111… |
… | …00000011010110100011 |
3 | 1111101010121121201202221 |
4 | 12021111130003112203 |
5 | 23404423043242011 |
6 | 522004224251511 |
7 | 42340661366545 |
oct | 6112534032643 |
9 | 1441117551687 |
10 | 422340212131 |
11 | 153128048432 |
12 | 69a28a70b97 |
13 | 30a98aca386 |
14 | 166271c3695 |
15 | aebcd2a971 |
hex | 62557035a3 |
422340212131 has 4 divisors (see below), whose sum is σ = 422342330632. Its totient is φ = 422338093632.
The previous prime is 422340212117. The next prime is 422340212201. The reversal of 422340212131 is 131212043224.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 422340212131 - 227 = 422205994403 is a prime.
It is a super-2 number, since 2×4223402121312 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 422340212096 and 422340212105.
It is not an unprimeable number, because it can be changed into a prime (422340212111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 725070 + ... + 1170643.
It is an arithmetic number, because the mean of its divisors is an integer number (105585582658).
Almost surely, 2422340212131 is an apocalyptic number.
422340212131 is a deficient number, since it is larger than the sum of its proper divisors (2118501).
422340212131 is a wasteful number, since it uses less digits than its factorization.
422340212131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2118500.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 422340212131 its reverse (131212043224), we get a palindrome (553552255355).
The spelling of 422340212131 in words is "four hundred twenty-two billion, three hundred forty million, two hundred twelve thousand, one hundred thirty-one".
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