Base | Representation |
---|---|
bin | 111101100111010101111… |
… | …111101111110011000111 |
3 | 112222210001000022200220001 |
4 | 331213111333233303013 |
5 | 1023333001024410143 |
6 | 13001044525422131 |
7 | 614622523023142 |
oct | 75472577576307 |
9 | 15883030280801 |
10 | 4234133044423 |
11 | 139275a7a1297 |
12 | 58472a70a947 |
13 | 24937a8447c9 |
14 | 108d0c733059 |
15 | 75215d0e14d |
hex | 3d9d5fefcc7 |
4234133044423 has 4 divisors (see below), whose sum is σ = 4234141216368. Its totient is φ = 4234124872480.
The previous prime is 4234133044397. The next prime is 4234133044447. The reversal of 4234133044423 is 3244403314324.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4234133044423 - 233 = 4225543109831 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4234133045423) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3252043 + ... + 4363948.
It is an arithmetic number, because the mean of its divisors is an integer number (1058535304092).
Almost surely, 24234133044423 is an apocalyptic number.
4234133044423 is a deficient number, since it is larger than the sum of its proper divisors (8171945).
4234133044423 is an equidigital number, since it uses as much as digits as its factorization.
4234133044423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8171944.
The product of its (nonzero) digits is 331776, while the sum is 37.
Adding to 4234133044423 its reverse (3244403314324), we get a palindrome (7478536358747).
The spelling of 4234133044423 in words is "four trillion, two hundred thirty-four billion, one hundred thirty-three million, forty-four thousand, four hundred twenty-three".
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