Base | Representation |
---|---|
bin | 10011010000100111110000… |
… | …01011011111010110000101 |
3 | 12112221212022102102111000111 |
4 | 21220103320023133112011 |
5 | 21022401001033100401 |
6 | 230024253332513021 |
7 | 11630604312130204 |
oct | 1150237013372605 |
9 | 175855272374014 |
10 | 42352541300101 |
11 | 1254968048761a |
12 | 490025847b771 |
13 | 1a82a9b05a106 |
14 | a65c3411d23b |
15 | 4d6a47dd5e51 |
hex | 2684f82df585 |
42352541300101 has 4 divisors (see below), whose sum is σ = 42352561111392. Its totient is φ = 42352521488812.
The previous prime is 42352541300081. The next prime is 42352541300191. The reversal of 42352541300101 is 10100314525324.
42352541300101 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 42352541300101 - 27 = 42352541299973 is a prime.
It is a super-2 number, since 2×423525413001012 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (42352541300191) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6249001 + ... + 11124526.
It is an arithmetic number, because the mean of its divisors is an integer number (10588140277848).
Almost surely, 242352541300101 is an apocalyptic number.
It is an amenable number.
42352541300101 is a deficient number, since it is larger than the sum of its proper divisors (19811291).
42352541300101 is a wasteful number, since it uses less digits than its factorization.
42352541300101 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19811290.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 42352541300101 its reverse (10100314525324), we get a palindrome (52452855825425).
It can be divided in two parts, 4235254 and 1300101, that added together give a palindrome (5535355).
The spelling of 42352541300101 in words is "forty-two trillion, three hundred fifty-two billion, five hundred forty-one million, three hundred thousand, one hundred one".
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