Base | Representation |
---|---|
bin | 111101101110001001001… |
… | …011000110100010100011 |
3 | 120000110212211120021011111 |
4 | 331232021023012202203 |
5 | 1023442424113010430 |
6 | 13004253220524151 |
7 | 615301456041016 |
oct | 75561113064243 |
9 | 16013784507144 |
10 | 4241434110115 |
11 | 1395866a87a84 |
12 | 586027850657 |
13 | 249c7232c617 |
14 | 10940225d37d |
15 | 754e1c97c2a |
hex | 3db892c68a3 |
4241434110115 has 64 divisors (see below), whose sum is σ = 5343985704960. Its totient is φ = 3227875200000.
The previous prime is 4241434110107. The next prime is 4241434110119. The reversal of 4241434110115 is 5110114341424.
4241434110115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 4241434110115 - 23 = 4241434110107 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is not an unprimeable number, because it can be changed into a prime (4241434110119) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3071276725 + ... + 3071278105.
It is an arithmetic number, because the mean of its divisors is an integer number (83499776640).
Almost surely, 24241434110115 is an apocalyptic number.
4241434110115 is a deficient number, since it is larger than the sum of its proper divisors (1102551594845).
4241434110115 is a wasteful number, since it uses less digits than its factorization.
4241434110115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2644.
The product of its (nonzero) digits is 7680, while the sum is 31.
Adding to 4241434110115 its reverse (5110114341424), we get a palindrome (9351548451539).
The spelling of 4241434110115 in words is "four trillion, two hundred forty-one billion, four hundred thirty-four million, one hundred ten thousand, one hundred fifteen".
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