Base | Representation |
---|---|
bin | 111101110000000000110… |
… | …010110100100110111101 |
3 | 120000200001200220101210211 |
4 | 331300000302310212331 |
5 | 1024011031344324013 |
6 | 13005224311432421 |
7 | 615402265314262 |
oct | 75600062644675 |
9 | 16020050811724 |
10 | 4243441011133 |
11 | 13966a6908465 |
12 | 5864a7985711 |
13 | 24a202051b0c |
14 | 1095529d3269 |
15 | 755ad07023d |
hex | 3dc00cb49bd |
4243441011133 has 8 divisors (see below), whose sum is σ = 4245838248960. Its totient is φ = 4241044144080.
The previous prime is 4243441011101. The next prime is 4243441011239. The reversal of 4243441011133 is 3311101443424.
4243441011133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4243441011133 - 25 = 4243441011101 is a prime.
It is a super-2 number, since 2×42434410111332 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 4243441011095 and 4243441011104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4243441011833) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24648808 + ... + 24820366.
It is an arithmetic number, because the mean of its divisors is an integer number (530729781120).
Almost surely, 24243441011133 is an apocalyptic number.
It is an amenable number.
4243441011133 is a deficient number, since it is larger than the sum of its proper divisors (2397237827).
4243441011133 is a wasteful number, since it uses less digits than its factorization.
4243441011133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 185387.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 4243441011133 its reverse (3311101443424), we get a palindrome (7554542454557).
The spelling of 4243441011133 in words is "four trillion, two hundred forty-three billion, four hundred forty-one million, eleven thousand, one hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •