Base | Representation |
---|---|
bin | 111101110000100010010… |
… | …011000100110000011011 |
3 | 120000201111212121011222221 |
4 | 331300202103010300123 |
5 | 1024013204244122021 |
6 | 13005400151324511 |
7 | 615422232154213 |
oct | 75604223046033 |
9 | 16021455534887 |
10 | 4244003114011 |
11 | 13969651316a1 |
12 | 586624080737 |
13 | 24a29163c07b |
14 | 1095a7513243 |
15 | 755e25a4241 |
hex | 3dc224c4c1b |
4244003114011 has 4 divisors (see below), whose sum is σ = 4244011317232. Its totient is φ = 4243994910792.
The previous prime is 4244003114003. The next prime is 4244003114033. The reversal of 4244003114011 is 1104113004424.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4244003114011 - 23 = 4244003114003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4244003111011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3269271 + ... + 4379056.
It is an arithmetic number, because the mean of its divisors is an integer number (1061002829308).
Almost surely, 24244003114011 is an apocalyptic number.
4244003114011 is a deficient number, since it is larger than the sum of its proper divisors (8203221).
4244003114011 is an equidigital number, since it uses as much as digits as its factorization.
4244003114011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8203220.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 4244003114011 its reverse (1104113004424), we get a palindrome (5348116118435).
The spelling of 4244003114011 in words is "four trillion, two hundred forty-four billion, three million, one hundred fourteen thousand, eleven".
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