Base | Representation |
---|---|
bin | 10011011000001010101011… |
… | …10011011111010001111111 |
3 | 12120212122112022102101101121 |
4 | 21230011111303133101333 |
5 | 21041122441341320242 |
6 | 230343332331051411 |
7 | 11655413243452153 |
oct | 1154052563372177 |
9 | 176778468371347 |
10 | 42611810104447 |
11 | 12639626a09751 |
12 | 4942554ba0b67 |
13 | 1aa1379493acc |
14 | a745cb919063 |
15 | 4dd66e7c7667 |
hex | 26c155cdf47f |
42611810104447 has 4 divisors (see below), whose sum is σ = 42615571419520. Its totient is φ = 42608048789376.
The previous prime is 42611810104361. The next prime is 42611810104477. The reversal of 42611810104447 is 74440101811624.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 42611810104447 - 215 = 42611810071679 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (42611810104477) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1880640543 + ... + 1880663200.
It is an arithmetic number, because the mean of its divisors is an integer number (10653892854880).
Almost surely, 242611810104447 is an apocalyptic number.
42611810104447 is a deficient number, since it is larger than the sum of its proper divisors (3761315073).
42611810104447 is a wasteful number, since it uses less digits than its factorization.
42611810104447 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3761315072.
The product of its (nonzero) digits is 172032, while the sum is 43.
The spelling of 42611810104447 in words is "forty-two trillion, six hundred eleven billion, eight hundred ten million, one hundred four thousand, four hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •