Base | Representation |
---|---|
bin | 1100011001101111111… |
… | …10111101010110011111 |
3 | 1111201221111111102221120 |
4 | 12030313332331112133 |
5 | 23440214044412112 |
6 | 523433320502023 |
7 | 42534112564044 |
oct | 6146776752637 |
9 | 1451844442846 |
10 | 426141013407 |
11 | 1547a854670a |
12 | 6a70991a913 |
13 | 31253385405 |
14 | 168a7cc31cb |
15 | b141853e8c |
hex | 6337fbd59f |
426141013407 has 4 divisors (see below), whose sum is σ = 568188017880. Its totient is φ = 284094008936.
The previous prime is 426141013399. The next prime is 426141013409. The reversal of 426141013407 is 704310141624.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 426141013407 - 23 = 426141013399 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (426141013409) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71023502232 + ... + 71023502237.
It is an arithmetic number, because the mean of its divisors is an integer number (142047004470).
Almost surely, 2426141013407 is an apocalyptic number.
426141013407 is a deficient number, since it is larger than the sum of its proper divisors (142047004473).
426141013407 is a wasteful number, since it uses less digits than its factorization.
426141013407 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 142047004472.
The product of its (nonzero) digits is 16128, while the sum is 33.
The spelling of 426141013407 in words is "four hundred twenty-six billion, one hundred forty-one million, thirteen thousand, four hundred seven".
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