Base | Representation |
---|---|
bin | 1100011010000110110… |
… | …11110111100100110101 |
3 | 1111202102220000112212111 |
4 | 12031003123313210311 |
5 | 23441112241010201 |
6 | 523504342451021 |
7 | 42541634623504 |
oct | 6150333674465 |
9 | 1452386015774 |
10 | 426333141301 |
11 | 154896a421a1 |
12 | 6a762133a71 |
13 | 31284114562 |
14 | 168c561683b |
15 | b153655b51 |
hex | 63436f7935 |
426333141301 has 4 divisors (see below), whose sum is σ = 432337833504. Its totient is φ = 420328449100.
The previous prime is 426333141281. The next prime is 426333141313. The reversal of 426333141301 is 103141333624.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 426333141301 - 219 = 426332617013 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (426333141401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3002345995 + ... + 3002346136.
It is an arithmetic number, because the mean of its divisors is an integer number (108084458376).
Almost surely, 2426333141301 is an apocalyptic number.
It is an amenable number.
426333141301 is a deficient number, since it is larger than the sum of its proper divisors (6004692203).
426333141301 is an equidigital number, since it uses as much as digits as its factorization.
426333141301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6004692202.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 426333141301 its reverse (103141333624), we get a palindrome (529474474925).
The spelling of 426333141301 in words is "four hundred twenty-six billion, three hundred thirty-three million, one hundred forty-one thousand, three hundred one".
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