Base | Representation |
---|---|
bin | 10011100011011101110000… |
… | …11001001001011001100111 |
3 | 12122020202112201021022102020 |
4 | 21301232320121021121213 |
5 | 21114003010331400403 |
6 | 231241533223514223 |
7 | 12025435235356146 |
oct | 1161567031113147 |
9 | 178222481238366 |
10 | 43000011200103 |
11 | 12779225350631 |
12 | 49a58348b8973 |
13 | 1acbb64519539 |
14 | a892d6a8975d |
15 | 4e87e0424453 |
hex | 271bb8649667 |
43000011200103 has 8 divisors (see below), whose sum is σ = 57416319830016. Its totient is φ = 28625188351800.
The previous prime is 43000011200017. The next prime is 43000011200177. The reversal of 43000011200103 is 30100211000034.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 43000011200103 - 212 = 43000011196007 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (43000011200203) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10371442983 + ... + 10371447128.
It is an arithmetic number, because the mean of its divisors is an integer number (7177039978752).
Almost surely, 243000011200103 is an apocalyptic number.
43000011200103 is a deficient number, since it is larger than the sum of its proper divisors (14416308629913).
43000011200103 is a wasteful number, since it uses less digits than its factorization.
43000011200103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20742890805.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 43000011200103 its reverse (30100211000034), we get a palindrome (73100222200137).
The spelling of 43000011200103 in words is "forty-three trillion, eleven million, two hundred thousand, one hundred three".
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