430012110112133 has 4 divisors (see below), whose sum is σ = 430105652015820. Its totient is φ = 429918568208448.

The previous prime is 430012110112127. The next prime is 430012110112157. The reversal of 430012110112133 is 331211011210034.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 150978404804929 + 279033705307204 = 12287327^2 + 16704302^2 .

It is a cyclic number.

It is not a de Polignac number, because 430012110112133 - 2⁶ = 430012110112069 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 430012110112099 and 430012110112108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (430012110112033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46770944948 + ... + 46770954141.

It is an arithmetic number, because the mean of its divisors is an integer number (107526413003955).

Almost surely, 2^{430012110112133} is an apocalyptic number.

It is an amenable number.

430012110112133 is a deficient number, since it is larger than the sum of its proper divisors (93541903687).

430012110112133 is an equidigital number, since it uses as much as digits as its factorization.

430012110112133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 93541903686.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 430012110112133 its reverse (331211011210034), we get a palindrome (761223121322167).

The spelling of 430012110112133 in words is "four hundred thirty trillion, twelve billion, one hundred ten million, one hundred twelve thousand, one hundred thirty-three".