Base | Representation |
---|---|
bin | 111110100100111110100… |
… | …001000110111110110010 |
3 | 120020002212002001202211212 |
4 | 332210332201012332302 |
5 | 1030424014122130114 |
6 | 13051311411440122 |
7 | 622454501332223 |
oct | 76447641067662 |
9 | 16202762052755 |
10 | 4300311130034 |
11 | 140882a584527 |
12 | 5955195b6042 |
13 | 25269622114a |
14 | 10c1c991124a |
15 | 76cdab25b3e |
hex | 3e93e846fb2 |
4300311130034 has 4 divisors (see below), whose sum is σ = 6450466695054. Its totient is φ = 2150155565016.
The previous prime is 4300311130007. The next prime is 4300311130081.
4300311130034 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 2373919807009 + 1926391323025 = 1540753^2 + 1387945^2 .
It is a junction number, because it is equal to n+sod(n) for n = 4300311129991 and 4300311130009.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075077782507 + ... + 1075077782510.
Almost surely, 24300311130034 is an apocalyptic number.
4300311130034 is a deficient number, since it is larger than the sum of its proper divisors (2150155565020).
4300311130034 is a wasteful number, since it uses less digits than its factorization.
4300311130034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2150155565019.
The product of its (nonzero) digits is 1296, while the sum is 23.
The spelling of 4300311130034 in words is "four trillion, three hundred billion, three hundred eleven million, one hundred thirty thousand, thirty-four".
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