43004412031 has 16 divisors (see below), whose sum is σ = 49391161344. Its totient is φ = 36678633984.

The previous prime is 43004412019. The next prime is 43004412037. The reversal of 43004412031 is 13021440034.

It is a cyclic number.

It is not a de Polignac number, because 43004412031 - 2¹¹ = 43004409983 is a prime.

It is a super-2 number, since 2×43004412031² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 43004411993 and 43004412011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43004412037) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4292430 + ... + 4302436.

It is an arithmetic number, because the mean of its divisors is an integer number (3086947584).

Almost surely, 2^43004412031 is an apocalyptic number.

43004412031 is a deficient number, since it is larger than the sum of its proper divisors (6386749313).

43004412031 is a wasteful number, since it uses less digits than its factorization.

43004412031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12990.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 43004412031 its reverse (13021440034), we get a palindrome (56025852065).

The spelling of 43004412031 in words is "forty-three billion, four million, four hundred twelve thousand, thirty-one".