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4301012314 = 22150506157
BaseRepresentation
bin1000000000101110…
…00011110101011010
3102002202010001201101
410000113003311122
532302024343224
61550441342014
7211404000334
oct40027036532
912082101641
104301012314
11190789a235
12a0049790a
135370b5201
142cb30c454
151a28d4044
hex1005c3d5a

4301012314 has 4 divisors (see below), whose sum is σ = 6451518474. Its totient is φ = 2150506156.

The previous prime is 4301012293. The next prime is 4301012333. The reversal of 4301012314 is 4132101034.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 4132101034 = 22066050517.

It can be written as a sum of positive squares in only one way, i.e., 2968397289 + 1332615025 = 54483^2 + 36505^2 .

It is a junction number, because it is equal to n+sod(n) for n = 4301012291 and 4301012300.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075253077 + ... + 1075253080.

Almost surely, 24301012314 is an apocalyptic number.

4301012314 is a deficient number, since it is larger than the sum of its proper divisors (2150506160).

4301012314 is a wasteful number, since it uses less digits than its factorization.

4301012314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2150506159.

The product of its (nonzero) digits is 288, while the sum is 19.

The square root of 4301012314 is about 65582.1036106650. The cubic root of 4301012314 is about 1626.2609307779.

Adding to 4301012314 its reverse (4132101034), we get a palindrome (8433113348).

The spelling of 4301012314 in words is "four billion, three hundred one million, twelve thousand, three hundred fourteen".

Divisors: 1 2 2150506157 4301012314