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43012104341 = 109339352337
BaseRepresentation
bin101000000011101110…
…001010000010010101
311010000120212021212112
4220003232022002111
51201042044314331
631432014400405
73051610566053
oct500356120225
9133016767775
1043012104341
1117272236678
128404800105
13409611441b
1421206451d3
1511bb16c32b
hexa03b8a095

43012104341 has 4 divisors (see below), whose sum is σ = 43051457772. Its totient is φ = 42972750912.

The previous prime is 43012104329. The next prime is 43012104389. The reversal of 43012104341 is 14340121034.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 42689758225 + 322346116 = 206615^2 + 17954^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-43012104341 is a prime.

It is a super-2 number, since 2×430121043412 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43012109341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19675076 + ... + 19677261.

It is an arithmetic number, because the mean of its divisors is an integer number (10762864443).

Almost surely, 243012104341 is an apocalyptic number.

It is an amenable number.

43012104341 is a deficient number, since it is larger than the sum of its proper divisors (39353431).

43012104341 is a wasteful number, since it uses less digits than its factorization.

43012104341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39353430.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 43012104341 its reverse (14340121034), we get a palindrome (57352225375).

The spelling of 43012104341 in words is "forty-three billion, twelve million, one hundred four thousand, three hundred forty-one".

Divisors: 1 1093 39352337 43012104341