43014126133 has 4 divisors (see below), whose sum is σ = 46924501248. Its totient is φ = 39103751020.

The previous prime is 43014126119. The next prime is 43014126139. The reversal of 43014126133 is 33162141034.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 43014126133 - 2⁵ = 43014126101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43014126139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1955187541 + ... + 1955187562.

It is an arithmetic number, because the mean of its divisors is an integer number (11731125312).

Almost surely, 2^43014126133 is an apocalyptic number.

It is an amenable number.

43014126133 is a deficient number, since it is larger than the sum of its proper divisors (3910375115).

43014126133 is a wasteful number, since it uses less digits than its factorization.

43014126133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3910375114.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 43014126133 its reverse (33162141034), we get a palindrome (76176267167).

The spelling of 43014126133 in words is "forty-three billion, fourteen million, one hundred twenty-six thousand, one hundred thirty-three".