Base | Representation |
---|---|
bin | 10011100011111000001101… |
… | …10100111100100001001111 |
3 | 12122022010012101121022021112 |
4 | 21301330012310330201033 |
5 | 21114221101233341421 |
6 | 231252242312322235 |
7 | 12026450162313344 |
oct | 1161740664744117 |
9 | 178263171538245 |
10 | 43014212012111 |
11 | 127842523368aa |
12 | 49a85386a337b |
13 | 1b002b8608192 |
14 | a89c82ab67cb |
15 | 4e8d71ec245b |
hex | 271f06d3c84f |
43014212012111 has 4 divisors (see below), whose sum is σ = 43027641366552. Its totient is φ = 43000782657672.
The previous prime is 43014212012077. The next prime is 43014212012119. The reversal of 43014212012111 is 11121021241034.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43014212012111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (43014212012119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6714672416 + ... + 6714678821.
It is an arithmetic number, because the mean of its divisors is an integer number (10756910341638).
Almost surely, 243014212012111 is an apocalyptic number.
43014212012111 is a deficient number, since it is larger than the sum of its proper divisors (13429354441).
43014212012111 is a wasteful number, since it uses less digits than its factorization.
43014212012111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13429354440.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 43014212012111 its reverse (11121021241034), we get a palindrome (54135233253145).
The spelling of 43014212012111 in words is "forty-three trillion, fourteen billion, two hundred twelve million, twelve thousand, one hundred eleven".
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