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430203413113 = 1456329540851
BaseRepresentation
bin1100100001010100001…
…11110010001001111001
31112010102121121201200221
412100222013302021321
524022024033204423
6525344400100041
743036561451005
oct6205207621171
91463377551627
10430203413113
111564a267a741
126b462304621
133174cbb4116
1416b7163b705
15b2cd302e5d
hex642a1f2279

430203413113 has 4 divisors (see below), whose sum is σ = 430232968528. Its totient is φ = 430173857700.

The previous prime is 430203413111. The next prime is 430203413131. The reversal of 430203413113 is 311314302034.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 430203413113 - 21 = 430203413111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (430203413111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14755863 + ... + 14784988.

It is an arithmetic number, because the mean of its divisors is an integer number (107558242132).

Almost surely, 2430203413113 is an apocalyptic number.

It is an amenable number.

430203413113 is a deficient number, since it is larger than the sum of its proper divisors (29555415).

430203413113 is a wasteful number, since it uses less digits than its factorization.

430203413113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29555414.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 430203413113 its reverse (311314302034), we get a palindrome (741517715147).

The spelling of 430203413113 in words is "four hundred thirty billion, two hundred three million, four hundred thirteen thousand, one hundred thirteen".

Divisors: 1 14563 29540851 430203413113