Base | Representation |
---|---|
bin | 101000000100111110… |
… | …010110001010100101 |
3 | 11010002001102021112111 |
4 | 220010332112022211 |
5 | 1201112440004131 |
6 | 31434045121021 |
7 | 3052254350260 |
oct | 500476261245 |
9 | 133061367474 |
10 | 43033125541 |
11 | 1728309416a |
12 | 840b859171 |
13 | 409a5945c3 |
14 | 2123357cd7 |
15 | 11bce20ab1 |
hex | a04f962a5 |
43033125541 has 4 divisors (see below), whose sum is σ = 49180714912. Its totient is φ = 36885536172.
The previous prime is 43033125533. The next prime is 43033125547. The reversal of 43033125541 is 14552133034.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 43033125541 - 23 = 43033125533 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (43033125547) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3073794675 + ... + 3073794688.
It is an arithmetic number, because the mean of its divisors is an integer number (12295178728).
Almost surely, 243033125541 is an apocalyptic number.
It is an amenable number.
43033125541 is a deficient number, since it is larger than the sum of its proper divisors (6147589371).
43033125541 is an equidigital number, since it uses as much as digits as its factorization.
43033125541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6147589370.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 43033125541 its reverse (14552133034), we get a palindrome (57585258575).
The spelling of 43033125541 in words is "forty-three billion, thirty-three million, one hundred twenty-five thousand, five hundred forty-one".
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