Base | Representation |
---|---|
bin | 101000000101100001… |
… | …110110011111110011 |
3 | 11010002200221010222121 |
4 | 220011201312133303 |
5 | 1201122330324021 |
6 | 31435020415111 |
7 | 3052426433614 |
oct | 500541663763 |
9 | 133080833877 |
10 | 43042433011 |
11 | 17288370a96 |
12 | 84129a7497 |
13 | 409c4a2b96 |
14 | 212469bc0b |
15 | 11bdb5d741 |
hex | a058767f3 |
43042433011 has 4 divisors (see below), whose sum is σ = 44430898624. Its totient is φ = 41653967400.
The previous prime is 43042432973. The next prime is 43042433033. The reversal of 43042433011 is 11033424034.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 43042433011 - 27 = 43042432883 is a prime.
It is a super-2 number, since 2×430424330112 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (43042433311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 694232760 + ... + 694232821.
It is an arithmetic number, because the mean of its divisors is an integer number (11107724656).
Almost surely, 243042433011 is an apocalyptic number.
43042433011 is a deficient number, since it is larger than the sum of its proper divisors (1388465613).
43042433011 is a wasteful number, since it uses less digits than its factorization.
43042433011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1388465612.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 43042433011 its reverse (11033424034), we get a palindrome (54075857045).
The spelling of 43042433011 in words is "forty-three billion, forty-two million, four hundred thirty-three thousand, eleven".
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