43055540121113 has 16 divisors (see below), whose sum is σ = 47229571905600. Its totient is φ = 39006837282240.

The previous prime is 43055540121107. The next prime is 43055540121119. The reversal of 43055540121113 is 31112104555034.

It is a happy number.

It is an interprime number because it is at equal distance from previous prime (43055540121107) and next prime (43055540121119).

It is a cyclic number.

It is not a de Polignac number, because 43055540121113 - 2¹² = 43055540117017 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (43055540121119) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 44868518 + ... + 45818063.

It is an arithmetic number, because the mean of its divisors is an integer number (2951848244100).

Almost surely, 2^{43055540121113} is an apocalyptic number.

It is an amenable number.

43055540121113 is a deficient number, since it is larger than the sum of its proper divisors (4174031784487).

43055540121113 is a wasteful number, since it uses less digits than its factorization.

43055540121113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 90687272.

The product of its (nonzero) digits is 36000, while the sum is 35.

Adding to 43055540121113 its reverse (31112104555034), we get a palindrome (74167644676147).

The spelling of 43055540121113 in words is "forty-three trillion, fifty-five billion, five hundred forty million, one hundred twenty-one thousand, one hundred thirteen".