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43104440133 = 326679171707
BaseRepresentation
bin101000001001001110…
…011000111101000101
311010021000121102202200
4220021032120331011
51201234214041013
631445113425113
73054111460446
oct501116307505
9133230542680
1043104440133
111730a372947
12842b70b199
1340ac2a35a1
14212c9dd2cd
1511c430ae73
hexa09398f45

43104440133 has 12 divisors (see below), whose sum is σ = 62263769568. Its totient is φ = 28735462440.

The previous prime is 43104440059. The next prime is 43104440167. The reversal of 43104440133 is 33104440134.

It is not a de Polignac number, because 43104440133 - 29 = 43104439621 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 43104440097 and 43104440106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43104440633) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 565266 + ... + 636972.

It is an arithmetic number, because the mean of its divisors is an integer number (5188647464).

Almost surely, 243104440133 is an apocalyptic number.

It is an amenable number.

43104440133 is a deficient number, since it is larger than the sum of its proper divisors (19159329435).

43104440133 is a wasteful number, since it uses less digits than its factorization.

43104440133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 138504 (or 138501 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 43104440133 its reverse (33104440134), we get a palindrome (76208880267).

Subtracting from 43104440133 its reverse (33104440134), we obtain a palindrome (9999999999).

The spelling of 43104440133 in words is "forty-three billion, one hundred four million, four hundred forty thousand, one hundred thirty-three".

Divisors: 1 3 9 66791 71707 200373 215121 601119 645363 4789382237 14368146711 43104440133