Base | Representation |
---|---|
bin | 110001000000010100111011… |
… | …0110111110110001010010011 |
3 | 2002112020022102201001012210121 |
4 | 1202000221312313312022103 |
5 | 422444340033020044103 |
6 | 4124435124540411111 |
7 | 156536405422461562 |
oct | 14200516667661223 |
9 | 2075208381035717 |
10 | 431053502112403 |
11 | 11538a844445565 |
12 | 40419081846a97 |
13 | 1566a22b4214c1 |
14 | 786315a919bd9 |
15 | 34c7a566db6bd |
hex | 1880a76df6293 |
431053502112403 has 4 divisors (see below), whose sum is σ = 431053632184840. Its totient is φ = 431053372039968.
The previous prime is 431053502112397. The next prime is 431053502112421. The reversal of 431053502112403 is 304211205350134.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 431053502112403 - 25 = 431053502112371 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (431053502115403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59931750 + ... + 66737707.
It is an arithmetic number, because the mean of its divisors is an integer number (107763408046210).
Almost surely, 2431053502112403 is an apocalyptic number.
431053502112403 is a deficient number, since it is larger than the sum of its proper divisors (130072437).
431053502112403 is a wasteful number, since it uses less digits than its factorization.
431053502112403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 130072436.
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 431053502112403 its reverse (304211205350134), we get a palindrome (735264707462537).
The spelling of 431053502112403 in words is "four hundred thirty-one trillion, fifty-three billion, five hundred two million, one hundred twelve thousand, four hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.091 sec. • engine limits •