4311004000111 has 4 divisors (see below), whose sum is σ = 4311017664352. Its totient is φ = 4310990335872.

The previous prime is 4311004000099. The next prime is 4311004000117. The reversal of 4311004000111 is 1110004001134.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4311004000111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4311004000117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6347415 + ... + 6993688.

It is an arithmetic number, because the mean of its divisors is an integer number (1077754416088).

Almost surely, 2^{4311004000111} is an apocalyptic number.

4311004000111 is a deficient number, since it is larger than the sum of its proper divisors (13664241).

4311004000111 is a wasteful number, since it uses less digits than its factorization.

4311004000111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13664240.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 4311004000111 its reverse (1110004001134), we get a palindrome (5421008001245).

The spelling of 4311004000111 in words is "four trillion, three hundred eleven billion, four million, one hundred eleven", and thus it is an aban number.