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43114013513 = 67643492739
BaseRepresentation
bin101000001001110010…
…111010001101001001
311010021200121210222022
4220021302322031021
51201244141413023
631450054534225
73054256032254
oct501162721511
9133250553868
1043114013513
111731481152a
128432967375
1340b1275bcc
14212ddb209b
1511c509c7c8
hexa09cba349

43114013513 has 4 divisors (see below), whose sum is σ = 43757506320. Its totient is φ = 42470520708.

The previous prime is 43114013489. The next prime is 43114013563. The reversal of 43114013513 is 31531041134.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 43114013513 - 222 = 43109819209 is a prime.

It is a super-3 number, since 3×431140135133 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (43114013563) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 321746303 + ... + 321746436.

It is an arithmetic number, because the mean of its divisors is an integer number (10939376580).

Almost surely, 243114013513 is an apocalyptic number.

It is an amenable number.

43114013513 is a deficient number, since it is larger than the sum of its proper divisors (643492807).

43114013513 is an equidigital number, since it uses as much as digits as its factorization.

43114013513 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 643492806.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 43114013513 its reverse (31531041134), we get a palindrome (74645054647).

The spelling of 43114013513 in words is "forty-three billion, one hundred fourteen million, thirteen thousand, five hundred thirteen".

Divisors: 1 67 643492739 43114013513