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43114013489 is a prime number
BaseRepresentation
bin101000001001110010…
…111010001100110001
311010021200121210221102
4220021302322030301
51201244141412424
631450054534145
73054256032221
oct501162721461
9133250553842
1043114013489
1117314811508
128432967355
1340b1275bb1
14212ddb2081
1511c509c7ae
hexa09cba331

43114013489 has 2 divisors, whose sum is σ = 43114013490. Its totient is φ = 43114013488.

The previous prime is 43114013471. The next prime is 43114013563. The reversal of 43114013489 is 98431041134.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 43064550400 + 49463089 = 207520^2 + 7033^2 .

It is a cyclic number.

It is not a de Polignac number, because 43114013489 - 232 = 38819046193 is a prime.

It is a super-3 number, since 3×431140134893 (a number of 33 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (43114073489) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21557006744 + 21557006745.

It is an arithmetic number, because the mean of its divisors is an integer number (21557006745).

Almost surely, 243114013489 is an apocalyptic number.

It is an amenable number.

43114013489 is a deficient number, since it is larger than the sum of its proper divisors (1).

43114013489 is an equidigital number, since it uses as much as digits as its factorization.

43114013489 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 38.

The spelling of 43114013489 in words is "forty-three billion, one hundred fourteen million, thirteen thousand, four hundred eighty-nine".