Base | Representation |
---|---|
bin | 10011100110110010001000… |
… | …11101001100100001011011 |
3 | 12122122122211220011201120001 |
4 | 21303121010131030201123 |
5 | 21122340013214041103 |
6 | 231410151223113431 |
7 | 12036612601144651 |
oct | 1163310435144133 |
9 | 178578756151501 |
10 | 43114030221403 |
11 | 12812615096949 |
12 | 4a039555a2877 |
13 | 1b0983556794b |
14 | a90a31934dd1 |
15 | 4eb76529d01d |
hex | 27364474c85b |
43114030221403 has 4 divisors (see below), whose sum is σ = 45383189706760. Its totient is φ = 40844870736048.
The previous prime is 43114030221373. The next prime is 43114030221421. The reversal of 43114030221403 is 30412203041134.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43114030221403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (43114030221433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1134579742650 + ... + 1134579742687.
It is an arithmetic number, because the mean of its divisors is an integer number (11345797426690).
Almost surely, 243114030221403 is an apocalyptic number.
43114030221403 is a deficient number, since it is larger than the sum of its proper divisors (2269159485357).
43114030221403 is a wasteful number, since it uses less digits than its factorization.
43114030221403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2269159485356.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 43114030221403 its reverse (30412203041134), we get a palindrome (73526233262537).
The spelling of 43114030221403 in words is "forty-three trillion, one hundred fourteen billion, thirty million, two hundred twenty-one thousand, four hundred three".
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