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43121042443 = 101921423083
BaseRepresentation
bin101000001010001101…
…101110010000001011
311010022011211220212001
4220022031232100023
51201302441324233
631450505331431
73054402545623
oct501215562013
9133264756761
1043121042443
1117318782466
128435196b77
1340b286733b
142130cc1883
1511c59da27d
hexa0a36e40b

43121042443 has 4 divisors (see below), whose sum is σ = 43121567448. Its totient is φ = 43120517440.

The previous prime is 43121042429. The next prime is 43121042491. The reversal of 43121042443 is 34424012134.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 34424012134 = 217212006067.

It is a cyclic number.

It is not a de Polignac number, because 43121042443 - 213 = 43121034251 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (43121042143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 109621 + ... + 313462.

It is an arithmetic number, because the mean of its divisors is an integer number (10780391862).

Almost surely, 243121042443 is an apocalyptic number.

43121042443 is a deficient number, since it is larger than the sum of its proper divisors (525005).

43121042443 is a wasteful number, since it uses less digits than its factorization.

43121042443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 525004.

The product of its (nonzero) digits is 9216, while the sum is 28.

Adding to 43121042443 its reverse (34424012134), we get a palindrome (77545054577).

The spelling of 43121042443 in words is "forty-three billion, one hundred twenty-one million, forty-two thousand, four hundred forty-three".

Divisors: 1 101921 423083 43121042443