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431214432001 = 4159103682239
BaseRepresentation
bin1100100011001100110…
…00100000111100000001
31112020001002000210212221
412101212120200330001
524031111343311001
6530032553451041
743103616123643
oct6214630407401
91466032023787
10431214432001
1115697133a141
126b6a4a10a81
13318814ab852
1416c29a16893
15b33be5e1a1
hex6466620f01

431214432001 has 4 divisors (see below), whose sum is σ = 431318118400. Its totient is φ = 431110745604.

The previous prime is 431214431969. The next prime is 431214432013. The reversal of 431214432001 is 100234412134.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 431214432001 - 25 = 431214431969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (431214432031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51836961 + ... + 51845278.

It is an arithmetic number, because the mean of its divisors is an integer number (107829529600).

Almost surely, 2431214432001 is an apocalyptic number.

It is an amenable number.

431214432001 is a deficient number, since it is larger than the sum of its proper divisors (103686399).

431214432001 is a wasteful number, since it uses less digits than its factorization.

431214432001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 103686398.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 431214432001 its reverse (100234412134), we get a palindrome (531448844135).

The spelling of 431214432001 in words is "four hundred thirty-one billion, two hundred fourteen million, four hundred thirty-two thousand, one".

Divisors: 1 4159 103682239 431214432001