43122311322133 has 4 divisors (see below), whose sum is σ = 43386865379488. Its totient is φ = 42857757264780.

The previous prime is 43122311322113. The next prime is 43122311322157. The reversal of 43122311322133 is 33122311322134.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 43122311322133 - 2¹⁷ = 43122311191061 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 43122311322095 and 43122311322104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43122311322113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 132277028433 + ... + 132277028758.

It is an arithmetic number, because the mean of its divisors is an integer number (10846716344872).

Almost surely, 2^{43122311322133} is an apocalyptic number.

It is an amenable number.

43122311322133 is a deficient number, since it is larger than the sum of its proper divisors (264554057355).

43122311322133 is a wasteful number, since it uses less digits than its factorization.

43122311322133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 264554057354.

The product of its digits is 15552, while the sum is 31.

Adding to 43122311322133 its reverse (33122311322134), we get a palindrome (76244622644267).

Subtracting from 43122311322133 its reverse (33122311322134), we obtain a palindrome (9999999999999).

The spelling of 43122311322133 in words is "forty-three trillion, one hundred twenty-two billion, three hundred eleven million, three hundred twenty-two thousand, one hundred thirty-three".