Base | Representation |
---|---|
bin | 10011100111000111000000… |
… | …01101010111011100100111 |
3 | 12122200201202122122122121012 |
4 | 21303203200031113130213 |
5 | 21123030434203032020 |
6 | 231415243023012435 |
7 | 12040460324300066 |
oct | 1163434015273447 |
9 | 178621678578535 |
10 | 43125233252135 |
11 | 12817343997731 |
12 | 4a05b6143a11b |
13 | 1b0a8cc56ac08 |
14 | a913b57761dd |
15 | 4ebbbda947c5 |
hex | 2738e0357727 |
43125233252135 has 16 divisors (see below), whose sum is σ = 51831938257920. Its totient is φ = 34445768660640.
The previous prime is 43125233252107. The next prime is 43125233252137. The reversal of 43125233252135 is 53125233252134.
It is not a de Polignac number, because 43125233252135 - 28 = 43125233251879 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 43125233252092 and 43125233252101.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (43125233252137) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15183230 + ... + 17798340.
It is an arithmetic number, because the mean of its divisors is an integer number (3239496141120).
Almost surely, 243125233252135 is an apocalyptic number.
43125233252135 is a deficient number, since it is larger than the sum of its proper divisors (8706705005785).
43125233252135 is a wasteful number, since it uses less digits than its factorization.
43125233252135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2620318.
The product of its digits is 648000, while the sum is 41.
Subtracting 43125233252135 from its reverse (53125233252134), we obtain a palindrome (9999999999999).
The spelling of 43125233252135 in words is "forty-three trillion, one hundred twenty-five billion, two hundred thirty-three million, two hundred fifty-two thousand, one hundred thirty-five".
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