Base | Representation |
---|---|
bin | 111110110000011101110… |
… | …101101000100010100101 |
3 | 120021021200211121201100220 |
4 | 332300131311220202211 |
5 | 1031124300311423013 |
6 | 13101111504354553 |
7 | 623402301104412 |
oct | 76603565504245 |
9 | 16237624551326 |
10 | 4312647764133 |
11 | 1412a902612a5 |
12 | 5979a1015a59 |
13 | 2538b103c237 |
14 | 10ca3a11b109 |
15 | 772adbdeb23 |
hex | 3ec1dd688a5 |
4312647764133 has 8 divisors (see below), whose sum is σ = 5822984323200. Its totient is φ = 2838704857248.
The previous prime is 4312647764039. The next prime is 4312647764171. The reversal of 4312647764133 is 3314677462134.
4312647764133 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 4312647764133 - 218 = 4312647501989 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4312647764233) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9098412768 + ... + 9098413241.
It is an arithmetic number, because the mean of its divisors is an integer number (727873040400).
Almost surely, 24312647764133 is an apocalyptic number.
It is an amenable number.
4312647764133 is a deficient number, since it is larger than the sum of its proper divisors (1510336559067).
4312647764133 is a wasteful number, since it uses less digits than its factorization.
4312647764133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18196826091.
The product of its digits is 6096384, while the sum is 51.
The spelling of 4312647764133 in words is "four trillion, three hundred twelve billion, six hundred forty-seven million, seven hundred sixty-four thousand, one hundred thirty-three".
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