Base | Representation |
---|---|
bin | 110001000010000111110111… |
… | …1100111110111011010011010 |
3 | 2002120002220120100011010011011 |
4 | 1202010033233213313122122 |
5 | 423012411044310232414 |
6 | 4125144350312524134 |
7 | 156563264343331342 |
oct | 14204175747673232 |
9 | 2076086510133134 |
10 | 431300341102234 |
11 | 1154754a163700a |
12 | 40458a8b6b064a |
13 | 156875a8643676 |
14 | 78710955b1d22 |
15 | 34ce1a1c59dc4 |
hex | 18843ef9f769a |
431300341102234 has 4 divisors (see below), whose sum is σ = 646950511653354. Its totient is φ = 215650170551116.
The previous prime is 431300341102229. The next prime is 431300341102243. The reversal of 431300341102234 is 432201143003134.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 245223541948225 + 186076799154009 = 15659615^2 + 13640997^2 .
It is a junction number, because it is equal to n+sod(n) for n = 431300341102196 and 431300341102205.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107825085275557 + ... + 107825085275560.
Almost surely, 2431300341102234 is an apocalyptic number.
431300341102234 is a deficient number, since it is larger than the sum of its proper divisors (215650170551120).
431300341102234 is a wasteful number, since it uses less digits than its factorization.
431300341102234 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 215650170551119.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 431300341102234 its reverse (432201143003134), we get a palindrome (863501484105368).
The spelling of 431300341102234 in words is "four hundred thirty-one trillion, three hundred billion, three hundred forty-one million, one hundred two thousand, two hundred thirty-four".
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