Base | Representation |
---|---|
bin | 110001000010011010011111… |
… | …1001110110100111000010011 |
3 | 2002120020201210022222210202221 |
4 | 1202010310333032310320103 |
5 | 423014034444320434303 |
6 | 4125215002424121511 |
7 | 156566211342411511 |
oct | 14204647716647023 |
9 | 2076221708883687 |
10 | 431340331421203 |
11 | 1154904530825a6 |
12 | 40464790306297 |
13 | 1568b2ac6b65b9 |
14 | 7872daa77d4b1 |
15 | 34d024297d4bd |
hex | 1884d3f3b4e13 |
431340331421203 has 4 divisors (see below), whose sum is σ = 431459915658640. Its totient is φ = 431220747183768.
The previous prime is 431340331421191. The next prime is 431340331421221. The reversal of 431340331421203 is 302124133043134.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 431340331421203 - 225 = 431340297866771 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (431340331421903) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59792113308 + ... + 59792120521.
It is an arithmetic number, because the mean of its divisors is an integer number (107864978914660).
Almost surely, 2431340331421203 is an apocalyptic number.
431340331421203 is a deficient number, since it is larger than the sum of its proper divisors (119584237437).
431340331421203 is a wasteful number, since it uses less digits than its factorization.
431340331421203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 119584237436.
The product of its (nonzero) digits is 62208, while the sum is 34.
Adding to 431340331421203 its reverse (302124133043134), we get a palindrome (733464464464337).
The spelling of 431340331421203 in words is "four hundred thirty-one trillion, three hundred forty billion, three hundred thirty-one million, four hundred twenty-one thousand, two hundred three".
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